Since the declared focal point was 200mm, the percentage error can be calculated:(|Theoretical-experimental|)/(Theoretical )*100=error 4.8%The focal point experimental is not within 7.88 mm of the indicated focal point. This means that the experimental value was not within the standard deviation of the actual value: there was a large variation in the data. This wide spread of data comes in part from Test 4, which had significant error with a focal length measured at 222.2mm. This error is probably caused by the image not being as sharp as possible on the screen and instead being slightly blurry. You can also measure the magnification. This can be done using distances or heights of the image and object. Both methods are shown below.Equation 4: Magnification using distances (trial 1) m=-d_i/d_o =-(71 cm)/(28 cm)=-2.53This indicates that the image is approximately twice and a half the size of the object. The negative sign indicates that the image is inverted. Equation 5: Magnification using heights (trial 1) m=h_i/h_o =-(-7.0 cm)/(2.8 cm)=-2.50 L' Image height is negative because the image has been reversed. This results in a magnification of -2.50, indicating that the image was larger than the object and was inverted. The two magnification values ​​can be compared using the percentage difference formula. If the percentage difference is low, the two equations for finding the magnification are equivalent.(|Value 1-Value 2|)/(1/2(Value 1+Value 2))*100=(-2.50—( -2.53)) /(1/2(-2.53+-2.50))*100=1.19% differenceThe low percentage difference means that the two equations both produce the same magnification and can be used interchangeably interchangeable to calculate the magnification. As a final experiment in part 2, half of the light was covered. The result is that the corresponding portion...... half of the sheet ...... in the lens equation can also be used for virtual images, such as those produced by convex lenses close to the object and by concave lenses in parts 3 and 4. Part 5 demonstrated one of the practical uses of lenses: correcting human vision. Converging lenses can force farsighted eyes to converge light so that the rays intersect on the retina to form a clear image. Diverging lenses do the opposite, causing myopic eyes to form an image in the retina and not further forward into the eye. Lenses with cylindrical components solve vision problems caused by non-spherical eyeballs. If we know how light interacts with a lens, we can predict where light rays will converge or appear to converge. With this information we can create lenses that force light to behave and form images where we want them to. This lab explored a practical application, adjusting human vision.